How much force is generated using the values 5 inches and 90 PSI?

How much force is generated using the values 5 inches and 90 PSI?

• A. 450 LBS
• B. 400 LBS
• C. 500 LBS
• D. 550 LBS

Answer: (A)

To determine the force generated using the values of 5 inches and 90 PSI, we can use the formula that relates pressure, area, and force. The formula is: \[ \text{Force} = \text{Pressure} \times \text{Area} \] In this case, pressure is given in pounds per square inch (PSI), and we need to calculate the area based on the diameter or radius. If we consider 5 inches to be the diameter of a circular area, the area can be calculated using the formula for the area of a circle: \[ \text{Area} = \pi \times \left(\frac{d}{2}\right)^2 \] Substituting 5 inches for \(d\): \[ \text{Area} = \pi \times \left(\frac{5}{2}\right)^2 \] \[ \text{Area} = \pi \times \left(2.5\right)^2 \] \[ \text{Area} = \pi \times 6.25 \] \[ \text{Area} \approx 19.63 \, \text{square inches} \] Now, using the pressure of 90 PSI: \[

To determine the force generated using the values of 5 inches and 90 PSI, we can use the formula that relates pressure, area, and force. The formula is:

[ \text{Force} = \text{Pressure} \times \text{Area} ]

In this case, pressure is given in pounds per square inch (PSI), and we need to calculate the area based on the diameter or radius. If we consider 5 inches to be the diameter of a circular area, the area can be calculated using the formula for the area of a circle:

[ \text{Area} = \pi \times \left(\frac{d}{2}\right)^2 ]

Substituting 5 inches for (d):

[ \text{Area} = \pi \times \left(\frac{5}{2}\right)^2 ]

[ \text{Area} = \pi \times \left(2.5\right)^2 ]

[ \text{Area} = \pi \times 6.25 ]

[ \text{Area} \approx 19.63 , \text{square inches} ]

Now, using the pressure of 90 PSI:

[